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$substrCP(表达式操作符)

$substrCP

返回字符串的子字符串。 子字符串从字符串中指定的 UTF-8 代码点(CP)索引(从零开始)处的字符开始,包含指定的代码点数量。

$substrCP has the following operator expression syntax:

{ $substrCP: [ <string expression>, <code point index>, <code point count> ] }
字段
类型
说明

string expression

字符串

要从中提取子字符串的字符串。 string expression可以是任何有效的表达式,只要它解析为字符串即可。 有关表达式的更多信息,请参阅表达式。

If the argument resolves to a value of null or refers to a field that is missing, $substrCP returns an empty string.

If the argument does not resolve to a string or null nor refers to a missing field, $substrCP returns an error.

code point index

数字

表示子串的起点。code point index 可以是任何有效表达式,只要它解析为一个非负整数。

code point count

数字

可以是任何有效的表达式,只要它解析为非负整数或可以表示为整数的数字(例如 2.0)。

例子
结果

{ $substrCP: [ "abcde", 1, 2 ] }

"bc"

{ $substrCP: [ "Hello World!", 6, 5 ] }

"World"

{ $substrCP: [ "cafétéria", 0, 5 ] }

"cafét"

{ $substrCP: [ "cafétéria", 5, 4 ] }

"éria"

{ $substrCP: [ "cafétéria", 7, 3 ] }

"ia"

{ $substrCP: [ "cafétéria", 3, 1 ] }

"é"

The $substrCP operator uses the code points to extract the substring. This behavior differs from the $substrBytes operator which extracts the substring by the number of bytes, where each character uses between one and four bytes.

考虑包含以下文档的 inventory 集合:

db.inventory.insertMany( [
{ _id: 1, item: "ABC1", quarter: "13Q1", description: "product 1" },
{ _id: 2, item: "ABC2", quarter: "13Q4", description: "product 2" },
{ _id: 3, item: "XYZ1", quarter: "14Q2", description: null }
] )

The following operation uses the $substrCP operator to separate the quarter value into a yearSubstring and a quarterSubstring. The quarterSubstring field represents the rest of the string from the specified byte index following the yearSubstring. It is calculated by subtracting the byte index from the length of the string using $strLenCP.

db.inventory.aggregate(
[
{
$project: {
item: 1,
yearSubstring: { $substrCP: [ "$quarter", 0, 2 ] },
quarterSubstring: {
$substrCP: [
"$quarter", 2, { $subtract: [ { $strLenCP: "$quarter" }, 2 ] }
]
}
}
}
]
)

操作返回以下结果:

{ _id: 1, item: "ABC1", yearSubstring: "13", quarterSubstring: "Q1" }
{ _id: 2, item: "ABC2", yearSubstring: "13", quarterSubstring: "Q4" }
{ _id: 3, item: "XYZ1", yearSubstring: "14", quarterSubstring: "Q2" }

使用以下文档创建 food 集合:

db.food.insertMany( [
{ _id: 1, name: "apple" },
{ _id: 2, name: "banana" },
{ _id: 3, name: "éclair" },
{ _id: 4, name: "hamburger" },
{ _id: 5, name: "jalapeño" },
{ _id: 6, name: "pizza" },
{ _id: 7, name: "tacos" },
{ _id: 8, name: "寿司sushi" }
] )

下面的示例使用 $substrCP 操作符从 name 值创建一个三字节的 menuCode:

db.food.aggregate(
[
{
$project: {
"name": 1,
"menuCode": { $substrCP: [ "$name", 0, 3 ] }
}
}
]
)

操作返回以下结果:

{ _id: 1, name: "apple", menuCode: "app" }
{ _id: 2, name: "banana", menuCode: "ban" }
{ _id: 3, name: "éclair", menuCode: "écl" }
{ _id: 4, name: "hamburger", menuCode: "ham" }
{ _id: 5, name: "jalapeño", menuCode: "jal" }
{ _id: 6, name: "pizza", menuCode: "piz" }
{ _id: 7, name: "tacos", menuCode: "tac" }
{ _id: 8, name: "寿司sushi", menuCode: "寿司s" }
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