SELECT COUNT(*) AS countFROM orders
| db.orders.aggregate( [ { $group: { _id: null, count: { $sum: 1 } } }] )
| |
SELECT SUM(price) AS totalFROM orders
| db.orders.aggregate( [ { $group: { _id: null, total: { $sum: "$price" } } }] )
| |
SELECT cust_id, SUM(price) AS totalFROM ordersGROUP BY cust_id
| db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }] )
| 对于每个唯一的 cust_id,对 price 字段求和。 |
SELECT cust_id, SUM(price) AS totalFROM ordersGROUP BY cust_idORDER BY total
| db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $sort: { total: 1 } }] )
| 对于每个唯一 cust_id,对 price 字段求和,且结果按总和排序。 |
SELECT cust_id, ord_date, SUM(price) AS totalFROM ordersGROUP BY cust_id, ord_date
| db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} }, total: { $sum: "$price" } } }] )
| 对于每个唯一的 cust_id 和 ord_date 分组,对 price 字段求和。不包括日期的时间部分。 |
SELECT cust_id, count(*)FROM ordersGROUP BY cust_idHAVING count(*) > 1
| db.orders.aggregate( [ { $group: { _id: "$cust_id", count: { $sum: 1 } } }, { $match: { count: { $gt: 1 } } }] )
| 对于具有多条记录的 cust_id,返回 cust_id 和相应的记录数。 |
SELECT cust_id, ord_date, SUM(price) AS totalFROM ordersGROUP BY cust_id, ord_dateHAVING total > 250
| db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} }, total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } }] )
| 对于每个唯一的 cust_id 和 ord_date 分组,对 price 字段求和并仅在总和大于 250 的情况下返回结果。不包括日期的时间部分。 |
SELECT cust_id, SUM(price) as totalFROM ordersWHERE status = 'A'GROUP BY cust_id
| db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }] )
| 对于状态为 A 的每个唯一的 cust_id,对 price 字段求和。 |
SELECT cust_id, SUM(price) as totalFROM ordersWHERE status = 'A'GROUP BY cust_idHAVING total > 250
| db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } }] )
| 对状态为 A 的每个唯一 cust_id,求 price 字段的总和,仅当总和大于 250 时才会返回。 |
SELECT cust_id, SUM(li.qty) as qtyFROM orders o, order_lineitem liWHERE li.order_id = o.idGROUP BY cust_id
| db.orders.aggregate( [ { $unwind: "$items" }, { $group: { _id: "$cust_id", qty: { $sum: "$items.qty" } } }] )
| 对于每个唯一的 cust_id,将与订单关联的相应订单项 qty 字段相加求和。 |
SELECT COUNT(*)FROM (SELECT cust_id, ord_date FROM orders GROUP BY cust_id, ord_date) as DerivedTable
| db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} } } }, { $group: { _id: null, count: { $sum: 1 } } }] )
| 计算不同 cust_id、ord_date 分组的数量。不包括日期的时间部分。 |